16c^2-28c+9=16c

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Solution for 16c^2-28c+9=16c equation:



16c^2-28c+9=16c
We move all terms to the left:
16c^2-28c+9-(16c)=0
We add all the numbers together, and all the variables
16c^2-44c+9=0
a = 16; b = -44; c = +9;
Δ = b2-4ac
Δ = -442-4·16·9
Δ = 1360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1360}=\sqrt{16*85}=\sqrt{16}*\sqrt{85}=4\sqrt{85}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-4\sqrt{85}}{2*16}=\frac{44-4\sqrt{85}}{32} $
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+4\sqrt{85}}{2*16}=\frac{44+4\sqrt{85}}{32} $

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